mak47
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What’s the point-slope form of a line with slope 2/5 that contains the point (-3,6)

Whats the pointslope form of a line with slope 25 that contains the point 36 class=

Respuesta :

[tex]\bf \begin{array}{ccccccccc} &&x_1&&y_1\\ % (a,b) &&(~ -3 &,& 6~) \end{array} \\\\\\ % slope = m slope = m\implies \cfrac{2}{5} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-6=\cfrac{2}{5}[x-(-3)]\implies y-6=\cfrac{2}{5}(x+3)[/tex]
MrGumby

Answer:

The equation of this line is y - 6 = 2/5(x + 3)

Step-by-step explanation:

To find this, start with the base form of point-slope form.

y - y1 = m(x - x1)

Now put the slope in for m and the two coordinates in for (x1, y1).

y - 6 = 2/5(x + 3)

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