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Calculate the magnitude of the angular momentum of the earth due its daily rotation about its own axis

Respuesta :

[tex]L=Iw[/tex]
[tex]I_{earth} = \frac{2}{5} r^{2}m= \frac{2}{5} (6371000^2m)(5.97*10^{24}kg)=9.71*10^ {37}[/tex]
[tex]L_{earth}=Iw=(9.71*10^ {37})(7.27*10^{-5})=7.07*10^{33}[/tex][/tex]

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