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What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y – 4 = –2/3(x – 6) and passes through the point (−2, −2)?

y = –2/3x – 10/3
y = –2/3x + 10/3
y = 3/2x - 1
y = 3/2x + 1

Respuesta :

the last equation is the correct one since if we multiply the slope of the given line by the slope of the line of this equation, you'll get -1, and if you substitute the coordinates of the given point in this equation, you'll get -2=3/2(-2)+1=-2 which means that this point belongs to the line of this equation

Answer:

y = 3/2x + 1

Step-by-step explanation:

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