Respuesta :

naǫ
Use the Pythagorean theorem:
[tex](\hbox{one leg})^2+(\hbox{the other leg})^2=(\hbox{hypotenuse})^2 \\ 6^2+6^2=x^2 \\ 6^2 \times 2=x^2 \\ \sqrt{6^2 \times 2}=x \\ \sqrt{6^2} \times \sqrt{2}=x \\ 6\sqrt{2}=x [/tex]
 
The length of the hypotenuse is 6√2 units.

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