Answer:
Soil required = 453 cm³
Step-by-step explanation:
Volume of cone [tex]=\frac{1}{3}\times \texttt{base area}\times \texttt{depth}[/tex]
Base area of cone [tex]=\pi r^2=\pi \times 3^2=9\pi cm^2[/tex]
Depth of cone = 8 cm
Volume of one cone [tex]=\frac{1}{3}\times 9\times \pi \times 8=75.39cm^3[/tex]
Volume of six cones = 6 x 75.39 = 452.39 cm³ = 453 cm³
Soil required = 453 cm³
