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At the bottom of the first hill, the 300 kg car is traveling 39.6 m/s. What is the kinetic energy of the car at this point? (ignore friction forces)

At the bottom of the first hill the 300 kg car is traveling 396 ms What is the kinetic energy of the car at this point ignore friction forces class=

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ANSWER:

1st option: 235,000 J

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 300 kg

Speed (v) = 39.6 m/s

We can calculate the kinetic energy using the following formula:

[tex]\begin{gathered} E_K=\frac{1}{2}mv^2 \\ \text{ We replacing:} \\ E_K=\frac{1}{2}\cdot300\cdot39.6^2 \\ E_K=235224\cong235000\text{ J} \end{gathered}[/tex]

The kinetic energy is 235000 J.

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