In the present question, we will calculate the area of each of the three regular figures that are parts of the irregular figure. They are:
A: a rectangle 4x3
B: a rectangle 9x3
C: a rectangle 3x5
The area of each rectangle is just the multiplication of the two sides, and the area of the irregular figure is the sum of them. From this, we calculate:
[tex]\begin{gathered} A_A=4\times3=12\text{ square units} \\ A_B=9\times3=27\text{ square units} \\ A_C=3\times5=15\text{ square units} \\ \\ A_{\text{Total}}=A_A+A_B+A_C \\ A_{\text{Total}}=12+27+15=54\text{ square units} \end{gathered}[/tex]
From the solution presented above, we are able to conclude that the area of the irregular figure is 54 square units.
