Since there are 52 cards in the standard deck
Since half of them are in black
Then the probability of getting a black card is
[tex]\begin{gathered} P(b)=\frac{\frac{52}{2}}{52} \\ P(b)=\frac{26}{52} \end{gathered}[/tex]Since there are 4 cards of 6, then
The probability of getting 6 is
[tex]P(6)=\frac{4}{52}[/tex]OR in probability means adding, then
The probability of getting a black card or a 6 is
[tex]\begin{gathered} P(b\text{ or 6)=}\frac{26}{52}+\frac{4}{52} \\ P(b\text{ or 6) =}\frac{30}{52} \end{gathered}[/tex]We can simplify it by dividing up and down by 2
[tex]\begin{gathered} P(b\text{ or 6)=}\frac{\frac{30}{2}}{\frac{52}{2}} \\ P(b\text{ or 6)=}\frac{15}{26} \end{gathered}[/tex]The answer is P(b or 6) = 30/52 OR 15/26