How many possible triangles can be created if measure of angle B equals pi over 6 comma a = 20, and b = 10?

First, we have to find the height using the following equation:
[tex]h\text{ = }b\sin (B)[/tex][tex]h\text{ = 10}\times\sin (\frac{\pi}{6})=5[/tex]We have found the height. If h < b < a, we can have only one triangle. That is the case. So the answer will be 1 triangle.