select all the sets of the value that could be the side length of Triangle z.sides are 7,4,10

We will determine if the sets are proportional, if they are, then those will be the sets of lengths that would belong to triangle z, that is:
a.
[tex]\frac{4}{8}=\frac{7}{11}=\frac{14}{10}\Rightarrow\frac{1}{2}\ne\frac{7}{11}\ne\frac{7}{5}[/tex]So, set a is not one.
b.
[tex]\frac{4}{10}=\frac{7}{17.5}=\frac{10}{25}\Rightarrow\frac{2}{5}=\frac{2}{5}=\frac{2}{5}[/tex]So, set b could be a set of lengths that belong to triangle z.
c.
[tex]\frac{4}{6}=\frac{7}{9}=\frac{10}{11}\Rightarrow\frac{2}{3}\ne\frac{7}{9}\ne\frac{10}{11}[/tex]So, set c is not one.
d.
[tex]\frac{4}{6}=\frac{7}{10.5}=\frac{10}{15}\Rightarrow\frac{2}{3}=\frac{2}{3}=\frac{2}{3}[/tex]So, set d could be a set of lengths that belong to triangle z.
e.
[tex]\frac{4}{8}=\frac{7}{14}=\frac{10}{20}\Rightarrow\frac{1}{2}=\frac{1}{2}=\frac{1}{2}[/tex]So, set e could be a set of lengths that beling to triangle z.
So, the options that could be candidate are: b, d & e.