1.a
We can rewrite the given information in an algebraic expression as follows:
[tex]\frac{3}{8}x=6[/tex]
where x represents the number of 3/8-inch thick books. Solving for x:
[tex]x=\frac{6}{\frac{3}{8}}[/tex]
We can rearrange the operation:
[tex]x=\frac{6}{3}\cdot8[/tex][tex]x=\frac{48}{3}[/tex][tex]x=16[/tex]
Then, we need 16 3/8-inch books to make a stack 6 inches tall.
1.b
To solve this exercise, we can use the same procedure as in 1.a.
0. Writing the information in an algebraic expression.
[tex]\frac{1}{2}x=2\cdot\frac{3}{4}[/tex]
where x represents the groups of 1/2 pound.
We can convert the mixed number into an improper fraction:
[tex]2\cdot\frac{3}{4}=\frac{2\cdot4+3}{4}=\frac{8+3}{4}=\frac{11}{4}[/tex]
2. Rewriting the operation:
[tex]\frac{1}{2}x=\frac{11}{4}[/tex][tex]x=\frac{\frac{11}{4}}{\frac{1}{2}}[/tex][tex]x=\frac{11\cdot2}{4\cdot1}[/tex][tex]x=\frac{22}{4}[/tex][tex]x=5.5[/tex]
We have 5.5 groups of 1/2 pounds in 2 (3/4) pounds.
Answer:
• 1.a 16
,
• 2.b 5.5
