Hello, I am having difficulty with this problem, thanks. Find the smallest numberFind the largest rational numberFind the smallest irrational number

In order to determine which of them is the smallest number, let's convert each number into a decimal number.
[tex]\sqrt[3]{9}=2.080083823\approx2.08[/tex][tex]\sqrt{3}=1.732050808\approx1.73[/tex][tex]\sqrt{\frac{1}{4}}=\frac{1}{2}=0.5[/tex][tex](-5)^{-2}=\frac{1}{(-5)^2}=\frac{1}{25}=0.04[/tex]Upon converting, we can easily that the smallest number is the fourth number which is (-5)^-2.
On the other hand, between the 4 numbers, there are only two rational numbers and these are the 3rd and the 4th number. Between the two, the largest rational number is the 3rd number which is √(1/4) equivalent to 0.5.
Lastly, between the 4 numbers, there are only two irrational numbers and these are the first and the second number. Between the two, the smallest irrational number is √3 which is equivalent to 1.73.