Answer:
a) 8 m/s²
b) 100 m
Explanation:
The acceleration of the train can be calculated as
[tex]a=\frac{v_f-v_i}{t}[/tex]Where vf is the final velocity, vi is the initial velocity, and t is the time. Replacing vf = 10 m/s, vi = 0 m/s, and t = 5 s, we get:
[tex]a=\frac{40\text{ m/s - 0 m/s}}{5\text{ s}}=\frac{40\text{ m/s}}{5\text{ s}}=8\text{ m/s}^2[/tex]Then, the distance traveled can be calculated using the following equation
[tex]x=v_it+\frac{1}{2}at^2[/tex]Replacing vi = 0 m/s, t = 5 s, and a = 8 m/s², we get
[tex]\begin{gathered} x=(0\text{ m/s\rparen\lparen5 s\rparen + }\frac{1}{2}(\text{ 8 m/s}^2)(5\text{ s\rparen}^2 \\ x=0\text{ m + }\frac{1}{2}(8\text{ m/s}^2)(25\text{ s\rparen} \\ x=0\text{ m+100 m} \\ x=100\text{ m} \end{gathered}[/tex]Therefore, the distance traveled by train was 100 m.
