The probability that he hits the bull's-eye in one shot is given by p = 0.87
Then, the probability that the hits the bull's-eye m times in n shots is given by:
[tex]P(m|n)=\frac{n!}{m!(n-m)!}p^m(1-p)^{n-m}[/tex]For n = 29 and m = 13 we have:
[tex]\begin{gathered} P(13|29)=\frac{29!}{13!16!}0.87^{13}\cdot0,13^{16} \\ P(13|29)=4.0\cdot10^{-8} \end{gathered}[/tex]