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Find the work done on a particle moving from J to Kif the magnitude and the direction of the force is givJ = (4,-9), K = (9,0), F = 01 - 2jAnswer

Find the work done on a particle moving from J to Kif the magnitude and the direction of the force is givJ 49 K 90 F 01 2jAnswer class=

Respuesta :

Answer:

Work done = -18 Joules

Explanation:

The force, F = 0i - 2j

The distance JK = K - J

JK = (9, 0) - (4, -9)

JK = (9-4, 0-(-9))

JK = (5, 9)

JK = 5i + 9j

The work done is the dot product of force and distance

Work done = F . JK

Work done = (0i - 2j) . (5i + 9j)

Work done = 0(5) + (-2)(9)

Work done = -18 Joules

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