Find the sine of each acute angle in the triangle below. Select all that apply:- 40/41- 41/9- 41/40- 9/40- 9/41

The sine relation is given by the length of the opposite leg to the angle over the length of the hypotenuse.
Using the angle between the sides 9 and 41, we have:
[tex]\sin (\theta_1)=\frac{40}{41}[/tex]Using the angle between 40 and 41, we have:
[tex]\sin (\theta_2)=\frac{9}{41}[/tex]Therefore the correct options are the first and fifth ones.