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This is what I need help with Given the equation below, 100 grams of AlCI and excess Ca, what mass of Al can be produced? Roundyour answer to two digits after the decimal point. Include proper units (abbreviated) and the substanceformula.3Ca + 2AICl3 -> 3CaCl2 + 2Al

This is what I need help with Given the equation below 100 grams of AlCI and excess Ca what mass of Al can be produced Roundyour answer to two digits after the class=

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Answer:

20.23grams

Explanations

Given the chemical equation below;

[tex]3Ca+2AlCl_3\rightarrow3CaCl_2+2Al[/tex]

Determine the mole of AlCl3

Mole = Mass/molar mass

mole of AlCl3 = 100/133.34

Mole of AlCl3 = 0.749moles

According to stoichiometry, 2 moles of AlCl3 produced 2 moles of Al, hence the mole of Al required is 0.749moles

Determine the mass of Al

Mass of Al = 0.749 * 26.98

Mass of Al = 20.23grams

Hence the mass of Al that can be produced is 20.23grams

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