In ∆ NOP , the measure of

We have six trigonometric ratios that can be applied to right triangles, that is, the triangles that have one angle equal to 90.
Before finding these ratios, we need to have a reference angle. In this case, the reference angle is Then, we have that the secant of an angle (in a right triangle) is given by:
[tex]\sec (\theta)=\frac{hyp}{adj}[/tex]That is, the secant is the ratio of the hypotenuse over the adjacent side of the angle. In this case, the angle is [tex]\text{sec(}\angle N)=\frac{hyp}{adj}=\frac{41}{9}\Rightarrow\sec (\angle N)=\frac{41}{9}[/tex]Therefore, the secant of the angle N is represented by the ratio 41/9.