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Trapezoid FGHJ is inscribed in P as shown. If FG = 24, JH = 10, and the diameter of P is 26, find the area of the trapezoid. (Hint: draw in auxiliary lines). Round to the nearest tenth if necessary.

Trapezoid FGHJ is inscribed in P as shown If FG 24 JH 10 and the diameter of P is 26 find the area of the trapezoid Hint draw in auxiliary lines Round to the ne class=

Respuesta :

Medunno13

Answer:

221

Step-by-step explanation:

If the diameter is 26, the radius is 13 (which is the same as the perpendicular from P to JH)

So, the area is

[tex]\frac{1}{2}(13)(24+10)=221[/tex]

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