If 130.0 g of steam at 200.0 °C absorbs 900.0 kJ of heat energy, what will be its increase in temperature?
Help pleaseeeeee

Answer:
t=1855.45 C
Explanation:
m=0.13kg t1=200C H=900000J Cp=4182J/kgC
h=m*cp*change in temperature
900*10^3=0.13*4182*(T-200)
1655.45=t-200
t=1855.45 C