In ΔCDE, the measure of ∠E=90°, the measure of ∠C=43°, and CD = 95 feet. Find the length of EC to the nearest tenth of a foot.

9514 1404 393
Answer:
69.5
Step-by-step explanation:
The useful trig relation in this case is ...
Cos = Adjacent/Hypotenuse
cos(43°) = x/95
x = 95×cos(43°) ≈ 69.5 . . . . feet