Answer:
D. 10 and 11
Step-by-step explanation:
This problem would use pythagorean theorem because we're finding the hypotenuse of a right triangle. This is its standard equation:
[tex]a {}^{2} + {b}^{2} = {c}^{2} [/tex]
The legs represent [tex]a[/tex] and [tex]b[/tex] respectively, and [tex]c[/tex] represents the hypotenuse. After plugging in the legs' respective values, the equation looks like this:
[tex]6^{2} + {9}^{2} = {c}^{2} →36 + 81 = {c}^{2} →117 = c^{2} [/tex]
To isolate [tex]c[/tex], you would find the square root of [tex]117[/tex]. In this case, we're just finding which integers[tex] \sqrt{117} [/tex] is between. [tex]\sqrt{100}(=10)[/tex] is the closest integer value below [tex]\sqrt{117}[/tex] and [tex]\sqrt{121}(=11)[/tex] is the closest integer value above [tex]\sqrt{117}[/tex]. So the answer is D. 10 and 11.