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The scores on a test given to all juniors in a school district are normally distributed with a mean of 79 and a standard deviation of 7. Find the percent of juniors whose score is no more than 86. The percent of juniors whose score is 86 or below is %.

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DAlTaie4707

Answer:

p (x -<-89) = p( _x_-_75_ < _ 89_- __75__) = p (z <_ 2) = 0.9773= 97.73%

7 7

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