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Potatoes - Samples: Assume the weights of Farmer Carl's potatoes are normally distributed with a mean of 7.0 ounces and a standard deviation of 1.2 ounces. He bags his potatoes in groups of 6. You buy a bag and the total weight is 36 ounces. Here we determine how lucky or unlucky you are.

Respuesta :

Solution :

Given that : mean, μ = 7, standard deviation, σ = 1.2

Therefore, the mean potato weight in the bag of 6 is

[tex]$\bar{x} = \frac{36}{6}$[/tex]

  = 6 ounces.

Here we have μ = 7, σ = 1.2, n = 6

So, z-score for [tex]$\bar{x} = 6 $[/tex] is

[tex]$z=\frac{\bar{x}-\mu}{\sigma/ \sqrt n}$[/tex]

   = [tex]$\frac{6-7}{1.2/\sqrt6} = -2.04$[/tex]

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