What is the z-score of a value that is 2.08 standard deviations greater than the mean?________ Express the answer as a decimal. please show me how to answer the question I'm confused. Thanks for whomever helps.
There should be a dialogue question. Let's assume we gathered files and they were distributed with a mean of 45 minutes and a standard deviation of 12 minutes.
Now let's assume some random person had to wait less than 20minutes Now to calculate the z-score we will use [tex] \frac{45-20}{12} = 2.08 [/tex] This gives us a z-score of 2.08