A particle traveled the distance of 6.6×[tex]10^{-19}[/tex] meters a a rate of 3.3×[tex]10^{-34}[/tex]. If distance equals rate times time, how many seconds did it take the particle to travel the specified distance?
A. 5.0x[tex]10^{14}[/tex] seconds
B. 2.0x[tex]10^{15}[/tex] seconds
C. 2.0x[tex]10^{-53}[/tex] seconds
D. 5.0x[tex]10x^{-53}[/tex] seconds

Respuesta :

Answer:

Distance (D) equals rate (R) times time (T): D = R x T

=> T = D/R = 6.6 x 10^-19/(3.3 x 10^-34) = 2 x 10^15 (m)

=> Option B is correct

Hope this helps!

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