Question 2 (2.5 points)
How many grams of hydrogen are needed to react with 17.2 mol of nitrogen.
N2 + 3H2 → 2NH3
O.3g H2
06.02 x 10^23g
O 104g H2
O2.02g H2

Respuesta :

Answer:

[tex]m_{H_{2}} = 51.6\,g[/tex]

Explanation:

The mass ratio of hydrogen to nitrogen is:

[tex]r = \frac{6\cdot (1\,\frac{g}{mol} )}{2\cdot (14\,\frac{g}{mol} )}[/tex]

[tex]r = \frac{6}{28}[/tex]

[tex]r = \frac{3}{14}[/tex]

The required mass of hydrogen is:

[tex]m_{H_{2}} = \frac{3}{14}\cdot (17.2\,mol)\cdot (14\,\frac{g}{mol} )[/tex]

[tex]m_{H_{2}} = 51.6\,g[/tex]