In the diagram, the hose is held straight up at theta degrees going at 6.5 m/s and with water falling down.. the distance between initial and final water displacement is 2m.. a fire hose held near the ground shoots water at a speed of 6.5 m/s. at what angle(s) should the nozle point in order that the water land 2.0 m away, why are there two different angles?
A fire hose held near the ground shoots water at a speed of 6.5 m/s. at what angle(s) should the nozle point in order that the water land 2.0 m away, why are there two different angles
There are two trajectories a projectile can travel to reach a destination, the high and low orbit.
The furthest destination can be obtained with an angle of Theta = 45°.
The high and low orbit are obtained with equal angles away from this Theta: Theta1 = 45°+Phi (high orbit) and Theta2 = 45°-Phi (low orbit).
formula for the inclined throw
Xm = (Vo^2 sin (2.Θ) / g)
solving for Theta gives
Theta = 13,83 °
or Theta = 90°-13,83° = 76,17°
See of it as mirrored around the 45° axis.
