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Aluminum reacts with sulfur to form aluminum sulfide according to the following reaction:

2 Al (s) + 3 S (s) → Al2S3 (s)

How many moles of sulfur will be need to produce 6 moles of aluminum sulfide?

a.
2 mol S

b.
3 mol S

c.
12 mol S

d.
15 mol S

e.
18 mol S

Respuesta :

Answer:

Explanation:

                    x mol         6 mol

2 Al (s) +    3 S (s) →       Al2S3 (s)

                 3 mol          1 mol

6 mol Al2S3  x 3 mol S/ 1 mol  Al2S3 = 18 mol S