PART ONE
In a 31 s interval, 320 hailstones strike a glass
window of area 1.455 m^2
at an angle 70◦ to the window surface. Each hailstone has a mass of
6 g and speed of 4.6 m/s. If the collisions are elastic, find the average
force on the window.
Answer in units of N.

PART TWO
Find the pressure on the window.
Answer in units of N/m^2


PART TWO

Respuesta :

Explanation:

Impulse = change in momentum

F Δt = m Δv

F (31 s) = (320 × 0.006 kg) (4.6 sin 70° m/s − (-4.6 sin 70° m/s))

F = 0.535 N

Pressure = force / area

P = F / A

P = 0.535 N / 1.455 m²

P = 0.368 Pa