The values of [tex]x[/tex] in the given equation are required.
The values of [tex]x[/tex] are [tex]6.27[/tex] or [tex]-1.27[/tex].
The equation is
[tex]x^2-5x-8=0[/tex]
Applying the quadratic formula
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\Rightarrow x=\dfrac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\times1\times \left(-8\right)}}{2\times1}\\\Rightarrow x=\dfrac{5\pm \sqrt{57}}{2}\\\Rightarrow x=\dfrac{5+ \sqrt{57}}{2},\dfrac{5- \sqrt{57}}{2}\\\Rightarrow x=6.27,-1.27[/tex]
The values of [tex]x[/tex] are [tex]6.27[/tex] or [tex]-1.27[/tex].
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