Answer:62.5 J
Explanation:
Given
Inductance(L)=5 H
resistance(R)[tex]=20 \Omega [/tex]
Voltage(V)=100 V
[tex]Current=\frac{100}{20}=5 A[/tex]
Current in L-R circuit is given by
[tex]I=I_0\left [ 1-e^{-\frac{Rt}{L}}\right ][/tex]
and Power=i^2R+Li\frac{di}{dt}[/tex]
For Steady state i.e. at[tex] t=\infty [/tex]
[tex]I=I_0[/tex]
Energy Stored is [tex]E=\frac{Li^2}{2}[/tex]
[tex]E=\frac{5\times 5^2}{2}=62.5 J[/tex]
