Write an equation of the horizontal asymptote for this function. Also, interpret what this asymptote means in the context of the problem (in terms of the fish population and the number of years since the fish were introduced into the lake.)

Answer:
Step-by-step explanation:
First, finding the horizontal asymptote:
[tex]\lim_{t \to \infty} = \frac{200+40t}{1+0.05t} = \frac{\frac{200}{t} 40 }{\frac{1}{t} 0.05} = 800[/tex]
In the context of the problem, the horizontal asymptote speaks about where the population of the fish is headed and capped.