Answer:
Option D. two complex roots
Step-by-step explanation:
we know that
In a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] the discriminant D is equal to
[tex]D=(b^{2}-4ac)[/tex]
in this problem we have
[tex]3x^{2} -2x+1=0[/tex]
so
[tex]a=3\\b=-2\\c=1[/tex]
substitute the values
[tex]D=(-2^{2}-4(3)(1))[/tex]
[tex]D=(4-12)[/tex]
[tex]D=-8[/tex]
The discriminant is negative
therefore
The quadratic equation has two complex roots
