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Beginning with commercial grade hydrochloric acid, 1.00 x 102 mL of a 12.4 M HCl is added to water to bring the total volume of the solution to 0.820L. What is the concentration of this new solution?

Respuesta :

Answer:

New concentration = 1.512 M

Explanation:

Using the equation for dilution;

M1V1 = M2V2

M1 = 12.4 M , V1 = 100 mL or 0.1 L

M2 = ? , V2 = 0.820 L

Therefore;

M2 = M1V1/V2

     = (12.4 × 0.1 )/(0.820L)

     = 1.512 M