(PLEASE SHOW YOUR WORK SO I CAN KNOW HOW TO DO THA NEXT ONE)
A circle with a central 13 centimeters. What is the area of sector JKL? Use 3.14 for [tex]\pi[/tex], and round your answer to the nearest tenth.

Respuesta :

[tex] {\huge {\mathfrak {\orange {Answer :-}}}} [/tex]

Area of a circle = [tex]\pi[/tex] * r^2

Let the angle that the sector subtends at the centre be 'x'.

Thus, area of a sector

= x/360 * [tex] \pi[/tex] * r^2

➡️ [tex] <b>Try solving yourself. </b>[/tex]