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At the beginning of the summer, the water level of a pond is 2 feet below its normal level. After an unusually dry summer, the water level of the pond dropped another 1 1/3 feet.

Write an equation to show how far above or below the normal water level the pond is at the end of the summer.

At the beginning of the summer the water level of a pond is 2 feet below its normal level After an unusually dry summer the water level of the pond dropped anot class=

Respuesta :

n = Normal water level
d = Dry water level

[tex]d = n - (2 + 1.333)[/tex]

Answer:

[tex]-3\frac{1}{3}[/tex]

Step-by-step explanation:

Since, after decreasing the water level by 2 feet,

Changes in water level = -2 feet,

Again after decreasing the water level by [tex]1\frac{1}{3}[/tex] feet,

Changes in water level = [tex]-1\frac{1}{3}[/tex] feet,

Thus, the total change in water level = [tex]-2-1\frac{1}{3}[/tex]

[tex]=-2-1-\frac{1}{3}[/tex]

[tex]=-3-\frac{1}{3}[/tex]

[tex]=-(3+\frac{1}{3})[/tex]

[tex]=-3\frac{1}{3}[/tex]

Which is the required expression.

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