larger is x the other is called y sum of squares is 394 x^2+y^2=394 one is 2 less that other x>y so y+2=x subsitute y+2 for x
(y+2)^2+y^2=394 expand y^2+4y+4+y^2=394 add like terms 2y^2+4y+4=394 divideboth sides by 2 y^2+2y+2=197 subtract 197 from both sides y^2+2y-195=0 factor (y+15)(y-13)=0 set each to zero y+15=0 y=-15 impossible since it is stated that they are positive so get rid of this solution y-13=0 y=13
