!!!Geometry, find the area of the rhombus!!

We have to use the property of rhombus that diagonals bisects each other and form 90 degree.
So we have to use pythagorean identity here[tex] x^2+5^2=13^2=>x^2=169-25 [/tex]
x=12
So the other diagonal is 12*2=24.
And area of rhombus =0.5(product of diagonals)
=0.5*10*24 =120