simplify
A) sin^2 theta
B) cos^2 theta
C) tan^ theta
D) 1

[tex] \frac{1-cos^2(\theta)}{cos^2(\theta)} [/tex]
we can use trigonometric identity
1-cos^2x =sin^2x
[tex] \frac{sin^2(\theta)}{cos^2(\theta)} [/tex]
now, we know that
tanx=sinx/cosx
[tex] =tan^2(\theta) [/tex].............Answer