Respuesta :

kenmyna
the  mass of  chlorine   that react  with  9.00 g  of Al to form AlCl3  is   35.465  grams

     Explanation
write  the equation  for  reaction
that is
2 Al +  3 Cl2  = 2 Al CL3
find  the moles  of    Al  reacted

moles = mass/molar mass

  9 g/ 27  g/mol = 0.333  moles  of Al

by use  of mole ratio between   Al to  Cl2    which is  2:3   find the moles of  Cl2

mole  of cl2 =  0.333 x3/2 = 0.4995  moles


mass of  Cl2  is therefore =  moles  x  molar mass

= 0.4995  x71 =  35.465  moles

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